Given the following state of memory, answer the questions about these machine la

Question

Given the following state of memory, answer the questions about these machine language instructions. Do not type any spaces in your answer.

Address                                          Contents
0000000000000001                  0000000010100010
0000000000000010                  0000000000010001
0000000000000011                  0000000011111111
0000000000000100                  0000000000000000

What are the contents of the A register after the execution of the following two instructions?
11000000
00000000 00000001

01110001
00000000 00000010

Explanation / Answer

00000000 instruction operator is '+'

So adding both instruction bits are: 1100000000000001 + 0111000100000010 === 100111011111111

Last 8 digits will be content.. so 11111111

---------------------------------------------------------------------------------------------------------------------------------------------------

Address will be adding last 8 digits of both instructions will give opcode for us.

00000001 + 00000010 = 00000011

So final answer will be 0000000000000011 0000000011111111

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