1. Write a C programme by using visual Studio for each : a) Write a function wit

Question

1. Write a C programme by using visual Studio for each :

a) Write a function with parameters that returen the largest of three integer arguments. So users could call your function (name: max3) to output the maximum of three input values.

b) Make a function outside of the main routine. And in the main routine, please call this function and print the harmonic mean. The harmonic mean of two numbers is obtained by taking the inverses of the two numbers, averaging them, and taking the inverse of the result. Write a function that takes two double arguments and returns the harmonic mean of the two numbers. In the main routine, call the function and print the mean.

-You may use this equation " 2*X*Y*(X+Y) "

c) Write a program to keep track of how many points a NBA player (e.g., Kobe Bryant) scored in each of 10 NBA basketball games. The frist six scores are entered when the array is initialized (int gameScore [10]={12, 5, 21, 15, 32, 10};), and then you are asked to input the player's scores for games 7~10 (Score are 21, 8, 11, and 14). After all the data is entered, the program loops through the 10 scores to compute average points per game.

Explanation / Answer

//C code part (a)

#include <stdio.h>

// function with parameters that returen the largest of three integer arguments.
int max3(int a,int b,int c)
{
int maxx = a;
if(b > maxx)
{
maxx = b;
}
if(c > maxx)
{
maxx = c;
}
return maxx;
}

int main()
{

int a = 4;
int b = 9;
int c = 3;
printf("Maximum of 3 numbers( %i , %i , %i ) is %i ", a,b,c, max3(a,b,c));

return 0;
}

/*
Output:

Maximum of 3 numbers( 4 , 9 , 3 ) is 9

*/

//C code part (b)

#include <stdio.h>

// function and print the harmonic mean. T
float harmonicMean(float a, float b)
{
return ( 2.0/( (1/a) + (1/b) ) );
}

int main()
{

float a1 = 4.0;
float b1 = 9.0;
printf("Harmonic mean of numbers( %f , %f ) is %f ", a1,b1, harmonicMean(a1,b1) );

return 0;
}

/*
Output:

Harmonic mean of numbers( 4.000000 , 9.000000 ) is 5.538462

*/

//C code part (c)

#include <stdio.h>

float Average(float scores[])
{
float sum = 0;
for (int i = 0; i < 10; ++i)
{
sum = sum + scores[i];
}
return sum/10.0;
}

int main()
{

float gameScore[10] = {12, 5, 21, 15, 32, 10};

for (int i = 7; i < 11; ++i)
{
printf("%s %i ", "Enter score of game", i);
scanf("%f",&gameScore[i-1]);
}
printf("Average Score = %f ", Average(gameScore));
return 0;
}

/*
Output:

Enter score of game 7
10
Enter score of game 8
1
Enter score of game 9
1
Enter score of game 10
1
Average Score = 10.800000
*/

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