The distance a freely falling object travels is x = 1/2 gt^2 where g - accelerat

Question

The distance a freely falling object travels is x = 1/2 gt^2 where g - acceleration due to gravity, 9.8 m/s^2 t - time in seconds x - distance traveled in meters. If you have taken calculus, you know that we can find the velocity of the object by taking the derivative of the preceding equation. That is, dx/dt = v = gt We can find the acceleration by taking the derivative again: dv/dt = a = g (a) create a function called free fall with a single input vector t that returns values for distance x, velocity v, and acceleration a. (b) Test your function with a time vector that ranges from 0 to 20 seconds. Display x, v, and a in table with column headings

Explanation / Answer

You need to run driver.m file only

driver.m

free_fall([0,1,4,8,12,16,20])

free_fall.m

function [x,v,a] = free_fall(t)
x = ones(1,size(t,2));
v = ones(1,size(t,2));
a = ones(1,size(t,2));
x = 1/2*9.8*t.^2;
v = 9.8*t;
a = 9.8*a;
fprintf(' Time x V a ');
table = [t',x',v',a'];
table
end

b) Table:

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.