could you explain to me how did we get this output i mean for the first question

Question

could you explain to me how did we get this output i mean for the first question "

H72

Hello has 6 characters. " How did we get them fron the printf there?

and second question how did we calculate the output ? thanks in advance

printf("He said: 'OK! \\ ") printf("He sold the painting for $%2.2f. ", 2.345e2); printf ("xcxdIn", 'H', 'H'); printf("%s has %d characters "Hellolt", strlen("Hellolt")); printf ("Is %-7.2e the same as %-7.2f? ", 1201.0, 1201.0) Solution He said: 'OK!'... He sold the painting for $234.50 H72 Hello has 6 characters. ls 1.20e+03 the same as 1201.00? 2) 9 points. int a 5, b 2; print %dIn", a, b) a a+b, print ("%d %d '', a, b), b a-b; printf %d ", a, b), ("%d a a-b; print ("%d %d a, b), n", b b-a b* 5+a, printf("%d %d n", a, b) a a 2-b print ("%d %d n", a, b); Solution 52 72 75 25 27 77

Explanation / Answer

1. printf("%c%d ",'H','H')

%c will print H and %d will print ascii of H which is 72

printf("%s has %d charecters. ",'Hello ',strlen("Hello "))

Hello has 5 charcater and ' ' is counted as one character so output will be and it will be used to as 'tab'

Hello has 6 characters.

2.

int a =5, b =2

printf("%d %d ",a,b) this statement is printing the value of a and seperated with space so output will be 5 2

a = a+b

a = 5+2 ; a =7, b =2 so output of printf("%d %d ",a,b) will be 7 2

b = a-b

b = 7-2 =5

printf("%d %d ",a,b) is 7 5

a = 7 b =5

a = a-b

a = 7-5 =2

so a =2 b =5

printf("%d %d ",a,b) is 2 5

b = b-a/b*5+a

= (5-2)/5*(5+2)

= 7

a =2 b =7

so printf("%d %d ",a,b) is 2 7

a= (a%2)-b

=(2%2)-7

= 0 -7 = 7

so printf("%d %d ",a,b) is -7 7

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