Using the monoalphabetic cipher, part of the ciphertext is the following: lutk t

Question

Using the monoalphabetic cipher, part of the ciphertext is the following: lutk tk luf lfkl (I have left a blank space between the words to make the problem easier). The following are the approximate relative frequencies of the whole ciphertext: f:12,l:11,j:8,x:8,t:7,v:7,e:7 o:5,g:4,h:4,u:4,n:4 y:2,m:3,w:2,i:1,q:1,r:1,d:1,k:1,z:1,a:1 b:0,c:0,p:0,s:0 You have to figure out what is the plaintext corresponding to the above ciphertext segment Using the monoalphabetic cipher, part of the ciphertext is the following: lutk tk luf lfkl (I have left a blank space between the words to make the problem easier). The following are the approximate relative frequencies of the whole ciphertext: f:12,l:11,j:8,x:8,t:7,v:7,e:7 o:5,g:4,h:4,u:4,n:4 y:2,m:3,w:2,i:1,q:1,r:1,d:1,k:1,z:1,a:1 b:0,c:0,p:0,s:0 You have to figure out what is the plaintext corresponding to the above ciphertext segment Using the monoalphabetic cipher, part of the ciphertext is the following: lutk tk luf lfkl (I have left a blank space between the words to make the problem easier). The following are the approximate relative frequencies of the whole ciphertext: f:12,l:11,j:8,x:8,t:7,v:7,e:7 o:5,g:4,h:4,u:4,n:4 y:2,m:3,w:2,i:1,q:1,r:1,d:1,k:1,z:1,a:1 b:0,c:0,p:0,s:0 You have to figure out what is the plaintext corresponding to the above ciphertext segment

Explanation / Answer

Ans: Here the Encrypted text is :- lutk tk luf lfkl

The relative frequency of cipher is :- f:12, :11, j:8, x:8, t:7, v:7, e:7, o:5, g:4, h:4, u:4, n:4 y:2,m:3,w:2,i:1,q:1,r:1,d:1,k:1,z:1,a:1, b:0,c:0,p:0,s:0

Normally,

In monoalphabatic substitution encryption, Relative frequency of character is E:12(for being a vowel), T:9(for being a consonant) and also most relative combined letters are TH(in case of consonant) and EA (in case of Vowel).

Here, In cipher text we have L - 4 times, k- 3 times and t- 2, u-2, f-2 times

Now using and analysing Normal English realative frequency to the cipher text which is = lutk tk luf lfkl=

THIS IS THE TEST

here lu stands for TH (remember most frequent combined consonant), Replace l = T, u = H in the cipher

and after analysing l = T, u = H, t = I, k = S, f = E.

So, Plain text would be THIS IS THE TEST

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