The question is to implement a function which computes the n region sign chart o

Question

The question is to implement a function which computes the n region sign chart of polynomial by using matlab code. I thought this way at the bottom, but it doesn't run the program, can you please help me to find out the problem. function [zs,ss]=signchart(f) end zs=unique(solve(f==0)); n=lenght(zs); ss=zeros(1,n+1); for i=1:length(zs) if i==1 ss(1)=sign(f(zs(1)-0.001)); elseif i==n ss(n)=sign(f(zs(n-1)+1));    else ss(i)=sign(f(zs(i-1)+zs(i)/2)); end end end
The question is to implement a function which computes the n region sign chart of polynomial by using matlab code. I thought this way at the bottom, but it doesn't run the program, can you please help me to find out the problem. function [zs,ss]=signchart(f) end zs=unique(solve(f==0)); n=lenght(zs); ss=zeros(1,n+1); for i=1:length(zs) if i==1 ss(1)=sign(f(zs(1)-0.001)); elseif i==n ss(n)=sign(f(zs(n-1)+1));    else ss(i)=sign(f(zs(i-1)+zs(i)/2)); end end end
The question is to implement a function which computes the n region sign chart of polynomial by using matlab code. I thought this way at the bottom, but it doesn't run the program, can you please help me to find out the problem. function [zs,ss]=signchart(f) end zs=unique(solve(f==0)); n=lenght(zs); ss=zeros(1,n+1); for i=1:length(zs) if i==1 ss(1)=sign(f(zs(1)-0.001)); elseif i==n ss(n)=sign(f(zs(n-1)+1));    else ss(i)=sign(f(zs(i-1)+zs(i)/2)); end end end

Explanation / Answer

You have written the end statement in the second line. This will mean to matlab that the function has ended there , hence throws an error. If you remove this, the program will run smoothly.

Also, there is an error in the spelling of length in the 4th line. Please correct the two.

function [zs,ss]=signchart(f)
  
zs=unique(solve(f==0));
n=length(zs);
ss=zeros(1,n+1);
for i=1:length(zs)
if i==1
ss(1)=sign(f(zs(1)-0.001));
elseif i==n
ss(n)=sign(f(zs(n-1)+1));
  
else
ss(i)=sign(f(zs(i-1)+zs(i)/2));
end
end
end

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