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Help with this please. I need to explain the program line by line. Annotate each

ID: 3766473 • Letter: H

Question

Help with this please. I need to explain the program line by line.

Annotate each line with the action it preforms using //annotation by the side of the line.

class Alpha

{

public static void main(String[] args)

{

   StringBuilder sb = new StringBuilder(26);

for (char ch = 'A'; ch <= 'G'; ch++)

sb.append(ch);

sb.append("u03b1");

sb.append("u03B2");

sb.append("u03c0");

System.out.println(sb.charAt(2));

System.out.println(sb.charAt(4));

System.out.println(sb.charAt(7));

System.out.println(sb.charAt(8));

System.out.println(sb.charAt(9));

}

}

Explanation / Answer

class Alpha

{

public static void main(String[] args)

{

   StringBuilder sb = new StringBuilder(26);//StringBuilder is mutable sequence of characters designed for use as a drop-in replacement for StringBuffer.it implemented under most because it is faster

for (char ch = 'A'; ch <= 'G'; ch++)//repeating loop A to G by specifying data type as char

sb.append(ch);//this method appends the string representation of the char argument in sequence

sb.append("u03b1");//Here unicode 03b1 appended to the string

sb.append("u03B2");//Here unicode 03B2 appended to the string

sb.append("u03c0");//Here unicode 03c0 appended to the string

System.out.println(sb.charAt(2));//It prints the char value at the specified index value of 2

System.out.println(sb.charAt(4));//It prints the char value at the specified index value of 4

System.out.println(sb.charAt(7));//It prints the char value at the specified index value of 7

System.out.println(sb.charAt(8));//It prints the char value at the specified index value of 8

System.out.println(sb.charAt(9));//It prints the char value at the specified index value of 9

}

}

OUTPUT:

ABCDEFG03b10B203c0

CE03b

Thank you.

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