****please write a version of a computer programming code in which the palindrom
ID: 3765681 • Letter: #
Question
****please write a version of a computer programming code in which the palindrome program does not ignore the capital letters?*** I need it by tonight!
This is the version of the program which the palindrome ignores capital letter
import java.util.Scanner;
public class PalindromeTester
{
//-----------------------------------------------------------------
// Tests strings to see if they are palindromes.
//-----------------------------------------------------------------
public static void main (String[] args)
{
String str, another = "y";
int left, right;
Scanner scan = new Scanner (System.in);
while (another.equals doesnot IgnoreCase("y")) // allows y or Y
{
System.out.println ("Enter a potential palindrome:");
str = scan.nextLine();
left = 0;
right = str.length() - 1;
while (str.charAt(left) == str.charAt(right) && left < right)
{
left++;
right--;
}
System.out.println();
if (left < right)
System.out.println ("That string is NOT a palindrome.");
else
System.out.println ("That string IS a palindrome.");
System.out.println();
System.out.print ("Test another palindrome (y/n)? ");
another = scan.nextLine();
}
}
}
Explanation / Answer
import java.io.*; 04 05 public class Palindrome 06 { 07 public static void main (String [] args) throws IOException 08 09 { 10 BufferedReader inFile = new BufferedReader (new FileReader ("pals.txt")); 11 String line; 12 line = inFile.readLine(); //initialize 13 String str, another = "y"; 14 int left, right; 15 String newString = ""; 16 17 18 while(line != null) // boolean expression 19 20 { 21 System.out.println(line); 22 line = inFile.readLine(); //read the next line 23 24 } 25 26 PrintWriter outFile = new PrintWriter (new FileWriter("output.txt")); 27 outFile.println("The string and if is a palindrome"); 28 inFile.close(); 29 outFile.close(); 30 31 while (another.equalsIgnoreCase("y")) // allows y or Y 32 { 33 str = inFile.readLine(); 34 left = 0; 35 right = str.length() - 1; 36 37 38 while (str.charAt(left) == str.charAt(right) && leftRelated Questions
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