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Bb Blackboard X Dab Blackboard x M Q Chapter 6 fl x M G Binary Searc x G Black B

ID: 3764379 • Letter: B

Question

Bb Blackboard X Dab Blackboard x M Q Chapter 6 fl x M G Binary Searc x G Black Box De x G What is the 5 x G length prop x L The Idiots G X New Tab x G Stepwise Re x GUnit Test C x C https:// myasucourses..asu.edu /webapps/portal/frameset jsp?tab tab group id 2 1&u; %2Fwebapps962Fblackboard962Fexecute%2Flauncher963Ftype%3DCourse%26id963D E ASU Home My ASU Colleges & Schools Map & Locations Contact Us Aaron U 18 Help Blackboard Home organizations Courses Remaining Time 1 hour, 07 minutes, 17 seconds Question Completion Status: QUESTION 21 3 points Save Answer Which of these techniques do not actually compare the contents of the array for the sake of checking for equality? if(arrayl equals(a (array2)) System.out.println("They are the same"); bool ean is Equal true; forint i 0; (i arrayl.length) && (isEqual true i++) f(a ayl ay2 is Equal false if(isEqual true) System.out.println("They are the same"); f(array 1 array2) System.out.println They are the same"); if(java utils.Arrays.equals (arrayl, array2)) System.out.println("They are the same");

Explanation / Answer

Techniques which donot compare contents of array for checking equality are:
//here if statement is checking if both are same array
if(array1.equals(array2))
   System.out.println("They are same");
//here also if statement is checking if both array are same array.
if(array1 == array2)
   System.out.println("They are same");

Explanation:
int array1[]={2,4,5,6};
int array2[]=array1;
//here array1 and array2 are same array
//now if we check
if(array1.equals(array2))//it will return true
{
  
}
//but if two arrays are different

int array1[]={2,4,5,6};
int array2[]={2,4,5,6};
//and checking
if(array1.equals(array2))//it will return false,as both are not same array
{
  
}
//but function Arrays.equals(array1,array2) checks each elements of array.If elements of arrays are equal then it return true else false

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