1.) Given int foo [50]; .... what is an equivalent way to represent: & foo [0] f

ID: 3754092 • Letter: 1

Question

1.) Given int foo [50]; .... what is an equivalent way to represent: & foo [0]

foo&

foo

foo [0]

None of the above

2.) Given an array defined as: int foo [5]; ... the following statement is never an issue: foo [5] = 12;

True

False

3.) Given the array: int foo [5] = {10,20,30,40, 50}; .... what would be printed from: printf ("%i", ++foo [3] );

4.) What is the array length (i.e., size) after this declaration: int foo [ ] = {10, 20, 40, 50, 60, 70};

a.)

foo&

b.)

foo

c.)

foo [0]

d.)

None of the above

1. Answer: b. foo
Reason: &foo[0] points to the first element of the array foo and so does foo. That is why they are equivalent.

2. Answer: False
Reason: Arrays start from 0 in C. So when an array of length 5 is declared, the array contains elements from 0 to 4.

3. Answer: d. 41
Reason: foo[3] points to the 4th element, ie. 40. And when prefixed by ++, the value is incremented before being printer.

4. Answer: c. 6
Reason: When 6 elements are assigned to the array, the length of the array becomes 6(0 to 5).

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