3. Calculate the total time required to transfer a 1000-KB (KB: Kilo-Byte) file

Question

3. Calculate the total time required to transfer a 1000-KB (KB: Kilo-Byte) file in the following cases, assuming a Round Trip Time (RTT) of 50ms, a packet size of 1KB, and an initial 2*RTT of handshaking to establish the connection before data is sent (2 points):

a) the bandwidth is 1.5Mbps (million bits per second), and data packets can be sent continuously.

b) the bandwidth is still 1.5Mbps, but we use a protocol with ACK to improve reliability. After we finish sending each data packet we must wait one RTT to receive ACK before sending the next.

Explanation / Answer

IF YOU HAVE ANY DOUBTS PLEASE COMMENT BELOW

ANS:

a)

  Initial Handshaking = 2 * R.T.T. = 2*50 ms = 100 ms

we can send continuously :

to send 1000KB file, & BandWidth is 1.5 Mbps..

So, time to transmit is 1000KB / 1.5 Mbps = 5333.33 ms

Total Time  = T.T. + Initial Handshaking time

      =  5333.33 + 100 = 5433.33 ms

b)

Initial Handshaking = 2 * R.T.T. = 2*50 ms = 100 ms

time to send 1 packet = 1KB / 1.5 Mbps = 16 / 3 ms

Inter packet gap = 1 R.T.T. = 50 ms

Total Time  = Initial Handshaking time + 1000 packets T.T.

+ 999 * R.T.T.(waiting time)

   =  100 + 1000(16/3) + 999(50)

= 55383.33 ms = 55.38 sec.

THANK YOU

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