Someone convert this code from Java to Ruby. bool isSet(Card a, Card b, Card c)

Question

Someone convert this code from Java to Ruby.

bool isSet(Card a, Card b, Card c) {
        if (!(((a.number == b.number)
                    && (b.number == c.number))
                    || ((a.number != b.number)
                    && ((a.number != c.number)
                    && (b.number != c.number))))) {
            return false;
        }
        
        if (!(((a.symbol == b.symbol)
                    && (b.symbol == c.symbol))
                    || ((a.symbol != b.symbol)
                    && ((a.symbol != c.symbol)
                    && (b.symbol != c.symbol))))) {
            return false;
        }
        
        if (!(((a.shading == b.shading)
                    && (b.shading == c.shading))
                    || ((a.shading != b.shading)
                    && ((a.shading != c.shading)
                    && (b.shading != c.shading))))) {
            return false;
        }
        
        if (!(((a.colour == b.colour)
                    && (b.colour == c.colour))
                    || ((a.colour != b.colour)
                    && ((a.colour != c.colour)
                    && (b.colour != c.colour))))) {
            return false;
        }
        
        return true;
}

Explanation / Answer

def is_set(a, b, c)
if not (((a.number == b.number)
&& (b.number == c.number))
|| ((a.number != b.number)
&& ((a.number != c.number)
&& (b.number != c.number))))
return false;
if not (((a.symbol == b.symbol)
&& (b.symbol == c.symbol))
|| ((a.symbol != b.symbol)
&& ((a.symbol != c.symbol)
&& (b.symbol != c.symbol))))
return false;
if not (((a.shading == b.shading)
&& (b.shading == c.shading))
|| ((a.shading != b.shading)
&& ((a.shading != c.shading)
&& (b.shading != c.shading))))
return false;
if not(((a.colour == b.colour)
&& (b.colour == c.colour))
|| ((a.colour != b.colour)
&& ((a.colour != c.colour)
&& (b.colour != c.colour))))
return false;

  
end

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