A milk carton can hold 28297 litres of milk . Each morning, a dairy farm ships c

Question

A milk carton can hold 28297 litres of milk . Each morning, a dairy farm ships cartons of milk to a local gocery store. The cost of producing one liter of is $0.38, and the profit of each carton of milk is $0.27. write a program on input and output file stream that does the following :promt the user to enter the amount of milk produced in the morning . Outputs the number of milk carton needed to hold mikl.( round answer to the nearest integer.). output the cost of producing milk. Output the profit for producing milk.

Explanation / Answer

#include<iostream>
#include<math.h>
using namespace std;

int main()
{

    long prod=0;
   cout<<"enter volume of milk produced this morning: ";
   cin>>prod;

   int cartons = (int)ceil(prod / 28297);
   double cost = 0.38*prod;
   cout<<" cost for producing milk is: "<<cost<<"$";
   double profit = 0.27*cartons;
   cout<<" profit earned is "<<profit;

}

I strongly believe that the amount of milk a carton can hold should be really less than 28297 liters. Anyway I have coded accordingly.

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