Design pseudocode for a program (name it Cylinder) to compute the volume of a cy

Question

Design pseudocode for a program (name it Cylinder) to compute the volume of a cylinder using the following formulas (PI is 3.14): Area = radius * radius * PI Volume = area * length The program reads the radius and length from the user and then computes the volume. Sample run 1: Enter radius: 5.5 Entered length: 12 The Volume is 1139.82 Sample run 2: Enter radius: 1.0 Entered length: 1.0 The Volume is 3.14 Sample run 3: Enter radius: 6.5 Entered length: 10.0 The Volume is 1326.65 Design pseudocode for a program (name it Cylinder) to compute the volume of a cylinder using the following formulas (PI is 3.14): Area = radius * radius * PI Volume = area * length The program reads the radius and length from the user and then computes the volume. Sample run 1: Enter radius: 5.5 Entered length: 12 The Volume is 1139.82 Sample run 2: Enter radius: 1.0 Entered length: 1.0 The Volume is 3.14 Sample run 3: Enter radius: 6.5 Entered length: 10.0 The Volume is 1326.65 Design pseudocode for a program (name it Cylinder) to compute the volume of a cylinder using the following formulas (PI is 3.14): Area = radius * radius * PI Volume = area * length The program reads the radius and length from the user and then computes the volume. Sample run 1: Enter radius: 5.5 Entered length: 12 The Volume is 1139.82 Sample run 2: Enter radius: 1.0 Entered length: 1.0 The Volume is 3.14 Sample run 3: Enter radius: 6.5 Entered length: 10.0 The Volume is 1326.65

Explanation / Answer

/*If you have any query do comment in the comment section else like the solution*/

Pseduo Code:

read input(radius);
read input(length);
PI=3.14;

area=radius*radius*PI;
volume=area*length;
print volume;

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.