Problem 2: Machine epsilon can also be thought of as the smallest number that wh

Question

Problem 2:

Machine epsilon can also be thought of as the smallest number that when added to one gives a number greater than 1. Below you will find an algorithm. Use this algorithm to create a m-file (script), determine the value for e, and compare with matlab’s defined value using the eps function. Allow for a maximum of 50 iterations.

Step 1: Set = 1.
Step2: If 1+ is less than or equal to 1, then go to Step5. Otherwise go to Step 3. Step 3: = /2
Step 4: Return to Step 2 Step 5: = 2 ×
Step 5: = 2 ×

thank you!! (everything in matlab plz)

Explanation / Answer

clc;

clear all;

close all;

epsi=1;

format long e

while (1)

if 1+epsi<=1

epsi=epsi*2;

break

else

epsi=epsi/2;

end

end

disp([epsi,eps]);

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