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(20 points) A system with a data rate (bandwidth) of 1 Mbps uses stop-and-wait p

ID: 3726230 • Letter: #

Question

(20 points) A system with a data rate (bandwidth) of 1 Mbps uses stop-and-wait protocol. If each packet carries 1000 bits of data, how long does it take to send 1 million bits of data (and ACKed) if the distance between the sender and receiver is 5000 Km and the propagation speed is 2 × 108 m/second? Assume the following 3. a. The waiting and processing delays are negligible. b. The ACK generation time (transmission time) is negligible C. No data or control packet is lost or damaged d. Ignore the overhead due to the control information added to the data portion of packets

Explanation / Answer

As per givcen requirement that needs to send 1000 frames.And also mentioned that, ignore the overhead.
Then, Data frame Transmission time = 1000 bits / 1,000,000 bits ( 1 Mbps = 1,000,000 bps)
= 1 ms
Given distance is 5000 km.
So that,data frame trip time = 5000 km / 200,000 km
= 25 ms
ACK transmission time = 0
ACK trip time = 5000 km / 200,000 km
= 25 ms
Delay for 1 frame = 1 + data frame trip time + ACK trip time
= 1 + 25 + 25
= 51 ms.
Total delay = 1000 51ms
= 1000bits 51 10-3
= 51s