Which diagrams CORRECTLY shows a cross of pure-breeding mice to produce heterozy

Question

Which diagrams CORRECTLY shows a cross of pure-breeding mice to produce heterozygous F1 mice, followed by a testcross of the F1 mice? Please explain reasoning behind your choice.

In deer mice, genes Q and T are on the same chromosome, 12 map units apart. Recessive mutationq results in mice with a quilted coat appearance, and recessive mutation t results in mice without tails. Alternate pure-breeding lines for these genes are crossed, and the F1 mice are testcrossed to double homozygous recessive mutant mice to produce offspring.

Which diagrams CORRECTLY shows a cross of pure-breeding mice to produce heterozygous F1 mice, followed by a testcross of the F1 mice? Please explain reasoning behind your choice. In deer mice, genes Q and T are on the same chromosome, 12 map units apart. Recessive mutationq results in mice with a quilted coat appearance, and recessive mutation t results in mice without tails. Alternate pure-breeding lines for these genes are crossed, and the F1 mice are testcrossed to double homozygous recessive mutant mice to produce offspring.

Explanation / Answer

Ans. Image 1 is Right. Explantion and Process shown Below.

Pure Breeding means = Homozygous.

A pure breeding Mice will Produce Heterozygous when it is Homozygous Dominant.
So, Homozygous Dominant = QQTT
Now,
QQTT will give gametes = QT
and a recessive Homozygous , qqtt
to which it is Crosses
qqtt will give gametes = qt

Now, On Cross,
QT X qt = QqTt (a Heterozygous Mouse)
now this hetrozygous mouse will be Test-Crossed
So,
QqTt will give gametes = QT, Qt, qT and qt
Test Cross with Homozygous Recessive
So, on Cross,
QT X qt = QqTt
Qt X qt = Qqtt
qT X qT = qqTt
qT X qt = qqtt

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