Explain please: Let A[1...n] be an array with n elements. Consider the prefix-av

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Explain please: Let A[1...n] be an array with n elements. Consider the prefix-average algorithm. See image:

Question 3 10 pts Let A[1..n] be an array with n elements. Consider the Prefix-Average algorithm, with the pseudocode below. Prefix-Average(A,n) 1.8=0 2. let B[1...n] be a new array 3, for j = 1 to n 4. 5. print s Which of the following is the correct loop invariant for the for loop? O At the start of each iteration j of the for loop, s represents the average of the elements in the prefix subarray A[0..j]. O At the start of each iteration j of the for loop, s represents the average of the elements in the prefix subarray 1.jj. O At the start of each iteration j of the for loop, s represents the average of the elements in the prefix subarray A[1.j+1]. At the start of each iteration j of the for loop, s represents the average of the elements in the prefix subarray A[1.j-1]. O

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The starting index of our array is 1 and prefix average calculates average all the previous values. Hence the value of s should be till (j-1) as A[j] is the last value which is added in prefix average to calculate new average. Therefore correct option is d. S represents the average of elements in prefix subarray A(1…..j-1)

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