Explain please? Our notes revealed that Newton\'s method fails to a find a root

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Explain please?

Our notes revealed that Newton's method fails to a find a root of the cubic: x^3 - 2*x + 2 when beginning at the guess x=1.Graph this cubic and find (by examining the graph and by trying a number of starting guesses) the value p such that Newton's converges on a root whenever we start with a guess that is less than p. sqrt(2/3) 0 -sqrt(2/3) For which function below will Newton's method ALWAYS succeed in finding a root, regardless of the initial input? abs(x)-1 O e^x-1 O sin(x)-1 O x^2-1 If f(x) = x*exp(-x*x) and we use Newton's Method to solve f(x) = 0 commencing from the guess x=1, then the Newton iterates decrease to zero increase to infinity hop around

Explanation / Answer

1) C

2) B

3) B

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