This question is very similar to what you will see on the Exam. Based on the con

Question

This question is very similar to what you will see on the Exam. Based on the concepts in the previous e what will be printed by the final line in the main method. public class Example { public static StringBuffer appendCat (Cat theCat) StringBuffer neNameheCatgetName newName appendC"Cat") return newName; public static void main (Stringll args) Cat myCat = new Cat ("Lily"); apendcatinvCat): Svstem.outaerintlnimvCat.cetName) public class Cat private StringBuffer name; // Note: name points to an addresa public Cat (StringBuffer name) public StringBuffer getName) t this. name name ; = retum name:

Explanation / Answer

Answer: (Note: there is a syntax error in the above program we need to change Cat myCat = new Cat(new StringBuffer("Lily")); in main method to compile the code successfully)

Stack for main()

Stack for appendCat()

Heap

Address Name Type Contents 1001 myCat Cat object myCat.name = Lily

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