WRITE C++ CCODE FOR THE FOLLOWING QUESTION USING CHAR AND C STRING You are requi

Question

WRITE C++ CCODE FOR THE FOLLOWING QUESTION USING CHAR AND C STRING

You are required to create a character array named “mywords” of size 10. Initialize it with random characters taken from user. Write C++ code that will reverse the order of the characters in this array.  
(You can use only 1 extra variable for this program, No extra array or more than 1 variable is allowed to be used).

Write a function that takes in two arrays of type char and length n, m and shuffles them in a way that their alternate characters are swapped. If one array is shorter than the other, then the longer array will continue with its own elements. For example
Array 1 = f g h u k m v
Array 2 = u h b d a s k
Output
Array 1 = u g b u a m k
Array 2 = f h h d k s

Write a function to find out how many digits are in a string. Your function should take one parameter: the string to search through. Your function should return a single integer: the number of digits contained in that string. Your function must have this prototype:

int countDigits(string);

For example, if the string was:

"Password123!"

Your function should return 3, as the string contains 3 digits: ‘1’, ‘2’, and ‘3’.

Explanation / Answer

#include<iostream>
using namespace std;
//method to reverse the order the elements in char array...
//using only one variable
void reverse(char a[],int n)
{
int i=0;
n--;
while(i<n)//reversing array
{
       char k=a[i];
       a[i]=a[n];
       a[n]=k;
       i++;
       n--;      
}  
}
void print_array(char a[],int n)
{
   int i=0;
   while(i<n)
   {
       cout<<a[i]<<" ";  
       i++;
   }
   cout<<" ";
}

//method to shuffle the two given arrays
void shuffle(char a[],int n,char b[],int m)
{
   if(n>m)
   n=m;
   int i=0;
   while(i<n)
   {
       if(i%2==0)//swapping at every even position
       {
           char k =a[i];
           a[i]=b[i];
           b[i]=k;  
       }
       i++;  
   }
     
  
}
//method to find the length of the array
int find_len(char a[])
{
   int i=0;
   while(a[i]!='')i++;
   return i;
  
}

//method to find the number of digits in given string

int countDigits(string s)
{
   int i=0;
   int count=0;//to count the number of digits
   while(s[i]!='')//end of the string...
   {
       if((int)s[i]>=48 && (int)s[i]<= 57)
       {
               count++;
       }
       i++;
   }
   return count;
}

//testing method
int main()
{
   char a[10];
   cout<<"Enter a random string:";
   cin>>a;
   int n = find_len(a);
   reverse(a,n);//method to reverse
   cout<<"Reversed string is:";print_array(a,n);
  
   char aa[20],bb[20];
   cout<<"Enter array 1:";
   cin>>aa;
   cout<<"Enter array 2:";
   cin>>bb;
   int x= find_len(aa),y=find_len(bb);
   shuffle(aa,x,bb,y);
   cout<<"Arrays after shuffling: ";
   cout<<"Array 1:";
   print_array(aa,x);
   cout<<"Array 2:";
   print_array(bb,y);
  
  
   string s;
   cout<<"Enter string to count digits:";
   cin>>s;
   int c=countDigits(s);
   cout<<"The number of digits in string :"<<c<<endl;
  
   return 0;
}

output:

Enter a random string:abcd
Reversed string is:d c b a
Enter array 1:fghukmv
Enter array 2:uhbdas
Arrays after shuffling:
Array 1:u g b u a m v
Array 2:f h h d k s
Enter string to count digits:Password123!
The number of digits in string :3

Process exited normally.
Press any key to continue . . .

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