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I\'ve made my code for the following problem and the function for area of the pa

ID: 3698640 • Letter: I

Question

I've made my code for the following problem and the function for area of the parachute. As of right now, I'm having trouble calling the area function in the parachute 4 file. I want to think its the variable I have set for tdeploy, but I do not know how to fix it to make it work.  

ENGR 1221 PARACHUTE PROJECT TASK 4: NEWTONIAN FRICTION EQUATION OVERVIEW The model used so far for drag is a form of Stoke's friction, i.e. This formula applies reasonably well to objects moving relatively slowly through a fluid. A better formulation of drag for our 'object' would be Newtonian friction; i.e., the Newtonian frictional force is given by Here Cd is the drag coefficient, p is the air density in kg/m3, A is the coss sertinnal area of the skydiver, and v is the velocity at which the skydiver is falling. Atmospheric densities range from about 0.85 kg/m at 4000 m to about 1.3 kg/m at sea level. A typical cross section area for a skydiver might be slightly under 1 m2, while a reasonable mass might be 80 kg more or less). The value of 1/6 for the coefficient in Stoke's drag formulation that you've been using as a constant for all speeds corresponds to a fall rate of about 35 m/s, which is somewhat above the middle speed between 0 and terminal velocity for a freefalling skydiver. With this as a background, you need to modify your script file to use the more realistic friction formula. The results will be simiacto what you had before, but after completing these Task 4 changes, you could realistically include variations in air density (Task PARACHUTE PROJECT TASK 4 STEPS FRICTION TO NEWTONIAN FRICTION Remove the use of k/m and change the acceleration to reflect Newtonian friction: 0.5CdpAi For Cd, use a value of 1. For p, use 1.1 kg/m2. For m, use 80 kg. For A, use the area of a circle, where the initial radius, [, is 5 m, the final radius i, is 3.6 m, and the Radius during expansion is calculated as described in the next section

Explanation / Answer

As the function defined in the area.m file is intended to return only one value, the enclosing '[ ]' for the Function return variable, A, is not needed. Also, in the last line must be changed to " A=pi*Radius^2; "as "Area" is not the return variable in this case, But "A" is.

Hence change "area.m" file to:

funtion A = area(ri, rf, t, tdeploy, topen)

c = ri;

b = (3*(rf-ri))/topen^2;

a = (-2*b)/(3*topen);

Radius = a*tdeploy^3+b*tdeploy^2+c;

A = pi*Radius^2;

end

This should solve the problem.

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