double foo(int count, double base) { return count * base; } int main (void) { in
ID: 3693639 • Letter: D
Question
double foo(int count, double base)
{
return count * base;
}
int main (void)
{
int n = 5;
double y = 1.1;
double x = foo(n, y);
// Statements to do more work, etc.
}
The call to foo copies the value of n to count, copies the value of y to base, and returns the product of count and base.
It will not compile because of there is no function prototype provided.
It will compile, but will not work correctly since y is passed by value.
The variable n is passed by value and is protected, but the variable y is passed by reference and is not protected.
(TCO 5) Consider the following code.
double foo(int count, double base)
{
return count * base;
}
int main (void)
{
int n = 5;
double y = 1.1;
double x = foo(n, y);
// Statements to do more work, etc.
}
The call to foo copies the value of n to count, copies the value of y to base, and returns the product of count and base.
It will not compile because of there is no function prototype provided.
It will compile, but will not work correctly since y is passed by value.
The variable n is passed by value and is protected, but the variable y is passed by reference and is not protected.
Explanation / Answer
Ans: The call to foo copies the value of n to count, copies the value of y to base, and returns the product of count and base.
There is no problem because we can declare and define the function at the same time, no need to provide a prototype first and then later define.
Again, here both the value are passed by value . so there is no error and it will return the value of the product of count and base.
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