Using python please answers questions R6.4 & R6.7 (6.4 goes onto the next page)

Question

Using python please answers questions R6.4 & R6.7 (6.4 goes onto the next page)
HW16 Review Questions 327 e.1 4 9 16 9 74 9 11 g.0 1 23 4 01 2 3 a [1, 2, 3, 4, 5, 4, 3, 2, 1, 0 R6.2 Consider the following list: What is the value of total after each of the following loops complete? a. total-0 for i in range (10) total- total ati] b.total0 for i in range (O, 10, 2): total total ati] c.total-0 for i in range (1, 10, 2): total total a[i] d. total 0 for i in range (2, 11): total total+ a[i] e. total while i

Explanation / Answer

Q6.4

Range(I,j,k) in python will give you list of values starting from i and ends with j-1 and every time it advance with step k

So range(1,5,1) will give [1,2,3,4]

This is the basic which is used in every loop below.

A.

a=[1,2,3,4,5,4,3,2,1,0]

for i in range(1,10):

    a[i]=a[i-1]

print (a)

Output: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]

Explanation:

Here range will give [1,2,3,4,5,6,7,8,9]

Then for every value of i

Example for i=1

A[1]=a[1-1]à a[1]=a[0] Hence a[1] is 2 before after that it will become 1.

So finaly we got

[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]

B. a=[1,2,3,4,5,4,3,2,1,0]

for i in range(9,0,-1):

    a[i]=a[i-1]

print (a)

Output: [1, 1, 2, 3, 4, 5, 4, 3, 2, 1]

Explanation:

Here range will have negative value as 3rd parameter. So it will advance in negative direction starting from 9 and move downwards 1 step So will give [9,8,7,6,5,4,3,2,1]

Then for every value of i

Example for i=9

A[9]=a[9-1]à a[9]=a[8] Hence a[9] is 0 before after that it will become 1.

So finaly we got

: [1, 1, 2, 3, 4, 5, 4, 3, 2, 1]

C:

a=[1,2,3,4,5,4,3,2,1,0]

for i in range(9):

    a[i]=a[i+1]

print (a)

Output: [2, 3, 4, 5, 4, 3, 2, 1, 0, 0]

Explanation:

hen for every value of I from[0-8]

Example for i=0

A[0]=a[0+1]à a[0]=a[1] Hence a[0] is 1 before after that it will become 2.

So finaly we got

[2, 3, 4, 5, 4, 3, 2, 1, 0, 0]

D.

a=[1,2,3,4,5,4,3,2,1,0]

for i in range(8,-8,-1):

    a[i]=a[i+1]

print (a)

Output: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

Explanation:

One thing to note in this is If we give negative index in list like

A[-1] then it will point list starting from Last with indexing start from 1.

So a[-2] will give you 1.

Consider this rule Here

E.

a=[1,2,3,4,5,4,3,2,1,0]

for i in range(1,10):

    a[i]=a[i]+a[i-1]

print (a)

Output: [1, 3, 6, 10, 15, 19, 22, 24, 25, 25]

F:

a=[1,2,3,4,5,4,3,2,1,0]

for i in range(1,10,2): # advance by 2

    a[i]=0

print (a)

output: [1, 0, 3, 0, 5, 0, 3, 0, 1, 0]

G:

a=[1,2,3,4,5,4,3,2,1,0]

for i in range(5):

    a[i+5]=a[i]

print (a)

Output:

[1, 2, 3, 4, 5, 1, 2, 3, 4, 5]

H:

a=[1,2,3,4,5,4,3,2,1,0]

for i in range(1,5):

    a[i]=a[9-i]

print (a)

Output:

[1, 1, 2, 3, 4, 4, 3, 2, 1, 0]

Q6.7

Q 6.7

A:           

values=[1,2,3,4,5,6,7,8,9,10]

for i in range(1,11):

    values[i]=i*i

print (values)

Explanation:

Here error is Index out of Range

Because in range function range(1,11) will give [1,2,3,4,5,6,7,8,9,10]

For every i you are doing i*I and assigning it to values[i].

So when i=10

Values[10]=10*10 but value[10] not exist. Index in values are from 0-9 only.

So this is wrong.

B. values=[]

for i in range(len(values)):

   

    values[i]=i*i

print (values)

Explanation:

Here List is empty so in range become range(0) which will give nothing and in output you will get empty List again

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