I have been having trouble with this C++ problem Your lease is up and it’s time

Question

I have been having trouble with this C++ problem

Your lease is up and it’s time to move. Unfortunately, you have a lot of stuff and you don’t want to spend too much time moving it because you’d rather be practicing your programming skills. Thankfully, you have friends who can help, though this help comes at a cost. Your friends can move 20 boxes an hour, but they require one 16 inch (diameter) pizza for this work. Write a function in C++ that takes the number of boxes you have and returns how much square feet of pizza you will have to buy. Use the function header:

sqFtPizza(int numBoxes)

and have it return the square feet of pizza as a float. Assume that the pizzas are perfectly round and that your friends require a full pizza even if they only work a partial hour. (In case you’ve forgotten your geometry, the area of a circle is pi*r^2. Use 3.14159 for pi.)

PLEASE NOTE: You don't have to include a main() function. The only thing that should be in your solution is the function definition.

Explanation / Answer

sqtFtPizza(int numBoxes)
{
   float sqft;
   float radius;
   radius=(float)8/20; //radius of pizza for one box
   radius=radius*numBoxes;//radius for num of boxes
   //for feets convert into feet as float ft=0.08333*radius;
   sqft=3.14152*radius*radius;//sqft=3.141*ft*ft;
   cout<<sqft<<"square inches";//cout<<sqft<<"square feet";
   //if freind wants full pizza use ceil function of math to round the number
  
}

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