(in c++) What will this program print? EXPLAIN every line. #include using namesp

Question

(in c++)

What will this program print? EXPLAIN every line.

#include

using namespace std;

int main()

{

int a[ ] = { 0, 1, 2, 3, 4} ;

int *p[ ] = { a, a+1, a+2, a+3, a+4 } ;

int **pp = p;

cout << a << " " << *a << endl;

cout << p << " " << *p << " " << **p << endl;

cout << pp << " " << *pp << " " << **pp << endl;

pp++;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

*pp++;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

*++pp;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

++*pp;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

pp = p;

**pp++;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

*++*pp;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

++**pp;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

return 0;

}

Explanation / Answer

#include <iostream>
using namespace std;

using namespace std;

int main()

{

int a[ ] = { 0, 1, 2, 3, 4} ;

int *p[ ] = { a, a+1, a+2, a+3, a+4 } ;

int **pp = p;

cout << a << " " << *a << endl; //Address of a and value of a[0]

cout << p << " " << *p << " " << **p << endl; //address of p , address of a , value of a[0]

cout << pp << " " << *pp << " " << **pp << endl; //address of p , address of a , value of a[0]

pp++;

cout << pp-p << " " << *pp-a << " " << **pp << endl; // pp will point to a+1 and p is poiting a so output will be 1 , and respectively 1 ,1

*pp++;

cout << pp-p << " " << *pp-a << " " << **pp << endl; // pp will point to a+2 and p is poiting a so output will be 2 , and respectively 2 ,2

*++pp;

cout << pp-p << " " << *pp-a << " " << **pp << endl; // same as above

++*pp;

cout << pp-p << " " << *pp-a << " " << **pp << endl; // Here pp is not incremented but *pp

pp = p;

**pp++;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

*++*pp;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

++**pp;

cout << pp-p << " " << *pp-a << " " << **pp << endl;

return 0;

}

0xbfaba1d8 0
0xbfaba1ec 0xbfaba1d8 0
0xbfaba1ec 0xbfaba1d8 0
1 1 1
2 2 2
3 3 3
3 4 4
1 1 1
1 2 2
1 2 3

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