Lisp Scheme Write a procedure in Lisp Scheme called charflip that takes a string

Question

Lisp Scheme
Write a procedure in Lisp Scheme called charflip that takes a string as a parameter and returns a copy of this string, flipping the case of every character in an odd position (index 1, 3, 5, etc..).
I suggest that you do this recursively. This means cons, car and cdr will come in handy, as will these functions:
• char-upper-case? • char-downcase • char-upcase • list->string • string->list
Here’s this function in action.
scheme@(guile-user)> (charflip "hatburg") $16 = "hAtBuRg" Lisp Scheme
Write a procedure in Lisp Scheme called charflip that takes a string as a parameter and returns a copy of this string, flipping the case of every character in an odd position (index 1, 3, 5, etc..).
I suggest that you do this recursively. This means cons, car and cdr will come in handy, as will these functions:
• char-upper-case? • char-downcase • char-upcase • list->string • string->list
Here’s this function in action.
scheme@(guile-user)> (charflip "hatburg") $16 = "hAtBuRg" Lisp Scheme
Write a procedure in Lisp Scheme called charflip that takes a string as a parameter and returns a copy of this string, flipping the case of every character in an odd position (index 1, 3, 5, etc..).
I suggest that you do this recursively. This means cons, car and cdr will come in handy, as will these functions:
• char-upper-case? • char-downcase • char-upcase • list->string • string->list
Here’s this function in action.
scheme@(guile-user)> (charflip "hatburg") $16 = "hAtBuRg"

Explanation / Answer

defun stringfun(x)

;case-sensitive comparison

(write(string ="sample lisp"))

(terpri)

"value of x"; This is a string

(-x))

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