A water tank consists of a cylindrical part of radius r and height h and a hemis
ID: 3665442 • Letter: A
Question
A water tank consists of a cylindrical part of radius r and height h and a hemispherical top. The tank is to be constructed to hold 600 m3 when
lled. The surface area of the cylindrical part is 2 rh, and its volume is r2h. The surface area of the hemispherical top is given by 2 r2, and its volume is given by 2 r3/3. The cost to construct the cylindrical part of the tank is $400 per square meter of surface area; the hemispherical part costs $600 per square meter. Use the fminbnd function to compute the radius that results in the least cost. Compute the corresponding height h
Explanation / Answer
Total_Volume = 600;
r = linspace(2, 10, 1000);
h = (600 - ((2*pi*r.^3)/3))./(pi * (r.^2));
Total_Cost = (400*2*pi.*r.*h) + (600*2*pi*r.^2);
%Now we will determine minumum cost and correspondence radius
[Min_Cost, Index] = min(Total_Cost)
Min_r = r(Index)
Corresponding_h = h(Index)
plot(r,Total_Cost)
xlabel ('Radius (Meter)')
ylabel ('Cost ($)')
title ('Cost versus Radius')
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