c program: what should be the answer given by this code? I typed the code into t

Question

c program: what should be the answer given by this code?

I typed the code into the program and got an output of 1, the teacher said this is not correct.

Two more things to clarify please: 1) How is % used? Ex. if I have 4%1 will the answer be 4 or Zero, since the remainder is ZERO?

2) Difference between ++i and i++???

Num = 2;

Int i =2;

Int result = ++i - --i / 2;

Printf(“result = %d, i = %d”);

Return 0

#include #include int main) float num; num 2 ; int i = 2; int result = ++i i , 2; printf( "result %d, i %d", result, i); return 0

Explanation / Answer

The answer for your program result =2 and i = 2

Int i =2 -- Thi initial value of i = 2;

Int result = ++i - --i / 2;

Here i is pre-incremented and post-incremented. (++i) where i = 2 becomes 3 and (--i), where i =3 becomes 2

result = 3 - 2/2 = 3-1 = 2

So Result = 2 and i = 2

Printf(“result = %d, i = %d”);

1) %   - gives reminder, 4 % 1 gives reminder zero (0)

2) ++i is pre increment. The value of i is incremented and the statement executed, i++ means post-increment. In post increment i is incremented after the statement execution

For example assume x = ++i, i = 5,

i is incremented first , then i = 6 and it assigned to x = i = 6

now assume x = i++ and i = 5

Here i is incremented after the assignment, so x = 5 and i = 6

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