i need a step by step solution please The total number of pages that make up the

Question

i need a step by step solution please

The total number of pages that make up the executable program is shown (no internal fragmentation). The total size of a frame is equal to 256 bytes The CPU needs to access data that is at the logical address 0 0 1 1 0 1 0 1 0 1 1 1 (12 bits) The size of a word in the system is 16 bits. What is the logical page number? What is the logical page offset? What is the total size in bvtes of the program? bytes Wha is the total size of a page in bvtes in this system? bytes The page of the data that was needed was put into the physical frame as shown above. Fill in the correct index of the page table with the exact data that it holds.

Explanation / Answer

total frame size is 256 byte means 128*16 bits so there are 128 words as word size is 16 bits so a page contains 128 words now the address contains 12 bit 001101010111 so the low order 7 bits contains offset(2^7=128) and high order 5 bits denotes page number which is in this case=6(page number) page offset is ::::the low order 7 bits i.e =87(page offset) since there are 11 pages in total so total program size=(11*256)Byte and total size of a page is=frame size=256 Byte AND after this i think you can easily do the E part that is 5th part of this question

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