i know to use Wfriction=FDcos180 but i dont know what D is? A small block with m

Question

i know to use Wfriction=FDcos180 but i dont know what D is?

A small block with mass 5.00 kg is released from rest at point A at the top rim of a hemispherical bowl that has radius R = 0.600 m. The block slides down the inside surface of the bowl. When it reaches point B at the bottom of the bowl, its speed is 2.8 m/s. As the block slides from point A to point B, how much work is done on it by friction? Ans. -9.8J As the block slides through point B, what is the magnitude of the normal force that the bowl exerts on the block? Ans. 114 N

Explanation / Answer

W = -5(9.8*0.6-0.5*2.8^2) = -9.8 J

b) N = mg+ mv^2/r = 5(9.8+2.8^2/0.6) = 114.33 N

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