i ich the 1\" and 2t place will win a prize are there to get the prize winners?
ID: 3066711 • Letter: I
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i ich the 1" and 2t place will win a prize are there to get the prize winners? b 18 students have appeared in a competition of wits in w Circle all that apphy How many possible ways Combination Multiplication Rule (Permutat 212 On building their own lightsaber, a young Padawan must choose a hilt out of 8 distinct designs, a focusing lens out of 3 types, an activator switch out of 2 switches, a power source of 4 kinds, and a kyber crystal out of 6 colors. How many possibilities of lightsabers can a Padawan make? G. Circle all that apply CMultiplication Rulg Permutation Combination ways In an office there are 6 women and 11 men. Michael, the best boss in the world, wants to restructure the party-planning committee so that it consists of 3 women and 2 men. How many d. different possibilities of committees can he make? Circle all that apply Multiplication Rule Permutation binat ways National Center for Education Statistics publishes information on U.S. engineers and scientists in Digest of ation Statistics. The table below presents a joint probability distribution for engineers and scientists by st degree obtained. Bachelors (8) Masters (M) Doctorate(D) Other (O) Totals eer (E) ist (s) ls 343 289 132 18 146 244 17 13 3 529 108 1000 ete the table above rom the study is randomly selected what is the probability thatExplanation / Answer
(b) Given 18 students participated in a competition and 1st, 2nd places are given prizes. since the places are given, the order in which one wins is important, i.e., the case of one getting 1st and 2nd is different. so, here we apply permutation. The number of ways of selecting 2 people of 18 is 18P2 = 18*17 = 306.
(c) The number of ways of lightsaber a Padawan can make is found out by multiplication rule because all the events given are independent of each other.
Number of possibilities = 8*3*2*4*6 = 1152.
(d) Here the order in which people are selected is not important, so we apply combination and the events of selecting woman and man are independent, so we also apply multiplication rule.
Number of ways of selecting 3 women and 2 men from a group of 6 women and 11 men is = 6C3*11C2 = 20*55 = 1100
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