This problem asks us to return all words in a string(which can contain weird cra

Question

This problem asks us to return all words in a string(which can contain weird crap like numbers and symbols) that are longer than five letters in a new array.

Here is what I have so far:

Java Code:
public static String[] getBigWords(String sentence){

//sentence = sentence.replaceAll("\d","");

String [] temp = null;
temp = sentence.split(" ");

int size = 0;
int k =0;
for(int i = 0; i < temp.length; i++) {
if(temp[i].length() > 5)
size++;
}

String[] big = new String[size];
for(int i = 0; i < temp.length; i++) {
if(temp[i].length() > 5){
big[k] = temp[i].toString();
k++;}
}
return big;
}
I am getting the following errors:

Problems Detected:
*****?*****Word '67000120909' incorrrectly returned in result
*****?*****Word '6A7B0C0V0D1E2S0D9D09' incorrrectly returned in result
*****?*****Word 'location' not returned in result
*****?*****Word 'son-in-law' incorrrectly returned in result

Fails When:
*****?*****Long non letter strings
*****?*****Punctuation
*****?*****Punctuation, duplicate words, beginning/middle/end

--> Is there a regex expression that has everything but characters in it so I can place it in my replace function?

Thanks.

Explanation / Answer

Please rate...

Program BigWords.java

===================================================

import java.util.Scanner;

class BigWords
{
    public static void main(String args[])
    {
        Scanner s=new Scanner(System.in);
        System.out.print("Enter the sentence: ");
        String sentence=s.nextLine();
        sentence=sentence+" ";
        String ar[]=new String[1000];
        ar=getBidWords(sentence);
        int i=0;
        while(ar[i]!=null)
        {
            System.out.print("""+ar[i]+"" ");
            i++;
        }
    }
    public static String[] getBidWords(String sentence)
    {
        int i=0,c=0,present=0;
        String words[]=new String[1000];
        String t="";
        while(i<sentence.length())
        {
            if((sentence.charAt(i)>='a' && sentence.charAt(i)<='z')||
                    (sentence.charAt(i)>='A' && sentence.charAt(i)<='Z'))
            {
                t=t.substring(0,present)+sentence.charAt(i);
                present++;
            }
            if(sentence.charAt(i)==' '||sentence.charAt(i)==' ')
            {
                if(t.length()>5)
                {
                    words[c]=t;
                    c++;
                }
                t="";
                present=0;
            }
            i++;
        }
        return words;
    }
}

=======================================================

Sample output:

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