can anyone provide me the solution, not the suggestion.Suggestion does not work.

Question

can anyone provide me the solution, not the suggestion.Suggestion does not work.Here are the questions.

Create a class named MyRectangle to represent rectangles. The required data fields are width, height, and color. Use double data type for width and height, and a String for color. Suppose that all rectangles are the same color. Use a static variable for color. You will need to provide the accessor methods for the properties and a method findArea() for computing the area of the rectangle.

rite a program to test your class MyRectangle. In the client program, create two MyRectangle objects. Assign a width and height to each of the two objects. Assign the first object the color red, and the second, yellow. Display all properties of both objects including their area.

I got output but both with yellow color.I want first red and second yellow.If you can fix and provide the solution please do it.here is my code.
class MyRectangle
{
private double width = 1.0;

private double height = 1.0;

private static String color ="White";

public MyRectangle()
{
width = 1.0;
height = 1.0;
}

public MyRectangle(double widthParam,double heightParam, String colorParam)
{
setWidth(widthParam);
setHeight(heightParam);
setColor(colorParam);
}

public double getWidth()
{
return width;
}

public void setWidth(double widthParam)
{
width = widthParam;
}

public double getHeight()
{
return height;
}

public void setHeight(double heightParam)
{
height = heightParam;
}

public String getColor()
{
return color;
}

public static void setColor(String colorParam)
{
color = colorParam;
}

public double findArea()
{
return getWidth()*getHeight();
}

public static void main(String [] args){
MyRectangle r1 = new MyRectangle(1.5,2,"Red");
MyRectangle r2 = new MyRectangle(3,5.5,"yellow");
print(r1,1);
print (r2,2);
}
public static void print(MyRectangle r, int n)
{System.out.println("Rectangle "+n);
System.out.println("height: "+r.getHeight());
System.out.println("width: "+r.getWidth());
System.out.println("color: "+r.getColor());
System.out.println("area: "+r.findArea()+" ");
}
}

Explanation / Answer

please rate - thanks

it's because color is static, which I believe was the way it was defined in the original post

the static says that the variable coloris associated with the class, not a specific instance of that class, so all the color will be the last value


class MyRectangle
{
private double width = 1.0;

private double height = 1.0;

private String color="white";

public MyRectangle()
{
width = 1.0;
height = 1.0;
}

public MyRectangle(double widthParam,double heightParam, String colorParam)
{
setWidth(widthParam);
setHeight(heightParam);
setColor(colorParam);


}

public double getWidth()
{
return width;
}

public void setWidth(double widthParam)
{
width = widthParam;
}

public double getHeight()
{
return height;
}

public void setHeight(double heightParam)
{
height = heightParam;
}

public String getColor()
{
return color;
}

public void setColor(String colorParam)
{
color = colorParam;
}

public double findArea()
{
return getWidth()*getHeight();
}

public static void main(String [] args){

MyRectangle r1 = new MyRectangle(1.5,2,"Red");
MyRectangle r2 = new MyRectangle(3,5.5,"yellow");
print(r1,1);
print (r2,2);

}
public static void print(MyRectangle r, int n)
{System.out.println("Rectangle "+n);
System.out.println("height: "+r.getHeight());
System.out.println("width: "+r.getWidth());
System.out.println("color: "+r.getColor());
System.out.println("area: "+r.findArea()+" ");
}
}

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