<p>When an object is falling because of gravity, the following<br />formula can

Question

<p>When an object is falling because of gravity, the following<br />formula can be used to determine the distance the object falls in a specific<br />time period.</p>
<p>D = &#189; gt^2</p>
<p>The variables in the formula are as follows: d is the<br />distance in meters, g is 9.8, and t is the amount of time in second that the<br />object has been falling.</p>
<p>Write a function named fallingDistance that accepts an<br />object&#8217;s falling time (in seconds) as an argument. The function should return<br />the distance, in meters, that the object has fallen during that time interval.<br />Write a program that demonstrates the function by calling it in a loop that<br />passes the values 1 though 10 as arguments, and displays the return value.</p>

Explanation / Answer

#include<iostream>

using namespace std;

float fallingDistance(int time)

{

return (0.5*9.8* static_cast<float> (time));

}

int main()

{

cout << time in seconds " << " distnace in meters. << endl;

for(int i=1; i<=10; i++)

{

cout << i << "           " << fallingDistance(i) << endl;

}

}

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