<p>The drawing below shows an adiabatic process.    The problem states
ID: 1893671 • Letter: #
Question
<p>The drawing below shows an adiabatic process.    The problem states that ΔUa = 0, because the energy of an ideal gas is only dependent on temperature.  So... dWrev(a)=-dqrev(a)</p><p>  <img src="https://s3.amazonaws.com/answer-board-image/3c515b8e-1890-47fe-a686-289000fad922.jpg" alt="image from custom entry tool" /></p>
<p>(Pressure versus Volume).</p>
<p>I understand path A, and path D+A, but I'm confused by path B+C</p>
<p>Path C is easy to understand: Cv(T)= dU/dt ∴<img src="https://s3.amazonaws.com/answer-board-image/cramster-equation-20111029232932634555277729893025170.gif" alt="" align="absmiddle" /> = Qrev(C).  No pressure volume work is done so this is the total energy change for path C.</p>
<p>I'm confused by path B.  The book says path B is adiabatic so q = 0</p>
<p>If you look at the graph you can clearly see that volume changes, but according to my book:</p>
<p>The reversible work done in path B is equal to...</p>
<p><img src="https://s3.amazonaws.com/answer-board-image/cramster-equation-20111029225086345552540852286536647.gif" alt="" width="108" height="32" align="absmiddle" /></p>
<p>This equation makes no sense to me.  How can you take the integral of a constant volume heat capacity when the volume changes?</p>
<p>I don't understand the math. Please clarify how this is possible</p>
Explanation / Answer
question is not clear....
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