The Host A sends a 1500 byte packet to Host B. You may assume that the transmiss

Question

The Host A sends a 1500 byte packet to Host B. You may assume that the transmission time for a single bit is negligible (but you must still compute transmission delays for the entire packet). The network is store and forward. In between the Host A and router is 1Mbps and 10 ms. Then the other side from router to Host B, its 15Mbps and 25ms.

1.Compute the transmission delay of the packet from Host A to the router.
2.Compute the transmission delay of the packet from the router to Host B.
3.Assume Host A sends the packet at time 0. When will the first bit arrive at Host B?
4.Assume Host A sends the packet at time 0. When will the last bit arrive at Host B (i.e., what is the end to end delay)?

Explanation / Answer

Given,

Size of the packet transmitted = 1500 bytes = 1500 x 8 = 12000 bits

Network is store and forward.

Between the Host A and router the transmission speed is 1Mbps and propagation delay is 10 ms

Between the router and Host B the transmission speed is 15Mbps and propagation delay is 25 ms

1Mbps = 106 bits per second

1second (s) =1000 mille seconds (ms)

Transmission delay = number of bits/ rate of transmission

1)         Number of bits (size of packet transmitted) = 12000bits

            Rate of transmission (transmission speed) = 1Mbps = 1000000 bps

Transmission delay of the packet from Host A to the router             = 12000/1000000

                                                                                                            = 12x10-3 seconds

                                                                                                            = 12 ms

2)         Number of bits (size of packet transmitted) = 12000bits

            Rate of transmission (transmission speed) = 15Mbps = 15000000 bps

Transmission delay of the packet from the router to Host     = 12000/15000000

                                                                                                            = 0.8x10-3 seconds

                                                                                                            = 0.8 ms

3)         Host A sends the packet at time 0, the first bit arrive at Host B

= (propagation delay of Host A + Transmission delay between Host A and router + Transmission delay between router and Host B)

= (10+12+0.8)

=22.8ms

4)         Host A sends the packet at time 0, the last bit arrive at Host B

                        =(propagation delay of Host A + Transmission delay between Host A and router + propagation delay of Host B +Transmission delay between router and Host B)

                        =(10+12+25+0.8)

                        =47.8ms

Hope this would help you.

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