Hi quick question.. lifesaver rating awarded. I compiled the following program a

Question

Hi quick question.. lifesaver rating awarded.
I compiled the following program and i'm tring to understand the output for data type float single_precision_number. I know that the decimal point moves put why the numbers are different. Please help. Also explain the output for double double_precision_number. Thanks

#include <iostream>
#include <iomanip>
using namespace std;

int main()
{
bool response = 234;
char character = 68;
int integer = 123.4567;
float single_precision_number = 1234.567890123456789;
double double_precision_number = 1234.567890123456789;


cout<<"response = "<<response<<endl;
cout<<"charater = "<<character<<endl;
cout<<"integer = "<<integer<<endl;
cout<<"single_precision_number = "<<setprecision (17)<<single_precision_number<<endl;
cout<<"double_precision_number = "<<setprecision (17)<<double_precision_number<<endl;

return 0;
}

Explanation / Answer

response = 1 charater = D integer = 123 single_precision_number = 1234.56787109375 double_precision_number = 1234.5678901234569 size of double is greater than float so it can hold more numbers than float. thats y in precision double can hold more digits than float :

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