Build a simple “English language” calculator that does the following: - Takes th

Question

Build a simple “English language” calculator that does the following:
- Takes three inputs from the keyboard, two of them single digits (0 to 9)
- Takes a char from the keyboard, representing one of the following five operations from the
keyboard: + (addition), - (subtraction), * (multiplication), / (division), and ^ (exponentiation).
- Outputs the description of the operation in plain English, as well as the numeric result

The operations should be translated into English as follows:
+ plus / divided by
- minus
* multiplied by ^ to the power
The switch…case statement might be helpful when translating the input values and operators into
words.
You need to consider three special situations:
1) one or two of the numbers is not a valid digit; output an error message.

2) the “operator” is not one of the allowed five operators; in that case output a message saying that the
operator is not a valid one.

3)for division there is a special constraint ; you cannot divide by 0, and you should therefore test
whether the second number is 0. If it is 0, you should output a message saying that division by zero is
not allowed and end your program.

Explanation / Answer

please rate - thanks

you didn't say if the digits should be input as integers or characters. I did it as integers

#include <iostream>
#include <cmath>              
using namespace std;
int main()                       
{
         char oper;
         int var1 = 0, var2 = 0;
        
        cout<<"enter number 1 operation number 2 (ex 1 + 2) -99 to exit ";
         cin>>var1;
         while(var1!=-99)
         {cin>>oper>>var2;
         if(var1<0||var1>9||var2<0||var2>9)
               cout<<"number must be 1 digit ";
         else
         {
         switch(oper)
         {case '+':
                   cout<<var1<<" plus "<<var2<<" = "<<var1+var2;
                   break;
          case '-':cout<<var1<<" minus "<<var2<<" = "<<var1-var2;
                   break;
          case '*':cout<<var1<<" multiplied by "<<var2<<" = "<<var1*var2;
                   break;
          case '/':if(var2==0)
                      cout<<var1<<" divided by "<<var2<<" is "<<"undefined";
                    else
                      cout<<var1<<" divided by "<<var2<<" = "<<(double)var1/var2;
                   break;
          case '^': cout<<var1<<" to the power "<<var2<<" = "<<pow((double)var1,var2);
                   break;
          default: cout<<"Invalid operator";
         
          }
          cout<<endl;
          }
          cout<<"enter number 1 operation number 2 (ex 1 + 2) -99 to exit ";
         cin>>var1;
          }
               
return 0;                    
}

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