So the code below is supposed to create 3 text files. Eachwith the names myFile1

Question

So the code below is supposed to create 3 text files. Eachwith the names myFile1, myFile2, and myFile3.
those names are stores in the variable 'buffer' but the linethat creates the txt files doesn't work when i try to pass a variable into it instead of physicallytyping "stringname.txt"
HOw can i pass this variable into that function or maybeanother function that creates txt files?

#include <stdio.h> #include <stdlib.h> #include <fstream> using namespace std; int main () {   char buffer [50];       for (int i=0;i<3;i++)   {    sprintf (buffer, "myFile%d.txt ", i);    ofstream fileout;    fileout.open(buffer);    printf(buffer);    }         return 0; } So the code below is supposed to create 3 text files. Eachwith the names myFile1, myFile2, and myFile3.
those names are stores in the variable 'buffer' but the linethat creates the txt files doesn't work when i try to pass a variable into it instead of physicallytyping "stringname.txt"
HOw can i pass this variable into that function or maybeanother function that creates txt files?

#include <stdio.h> #include <stdlib.h> #include <fstream> using namespace std; int main () {   char buffer [50];       for (int i=0;i<3;i++)   {    sprintf (buffer, "myFile%d.txt ", i);    ofstream fileout;    fileout.open(buffer);    printf(buffer);    }         return 0; }

Explanation / Answer

please rate - thanks I don't totally understand the question. but this will create 3files myFile1.txt 2 and 3 #include #include using namespace std; int main() { char buffer [50]={"myFilex.txt"}; ofstream out; for (char i='1';i

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