= (A.A+AC+AD+CD)(B+D)(A+B+C+D) =(A+AC+AD+CD)(B+D)(A+B+C+D) = (AB+ABC+ABD+BCD)(A+

Question

                                       = (A.A+AC+AD+CD)(B+D)(A+B+C+D)

                                       =(A+AC+AD+CD)(B+D)(A+B+C+D)

                                       = (AB+ABC+ABD+BCD)(A+B+C+D)

                                       = AB+ABD+ ABC+ABCD+AD+ACD+BCD+CD

                                       = ABCD+ABCD' +ABC'D+ABC' D' +A' BC'D+AB' C' D'                                         +AB' CD+AB' C'D' +A' BCD+A' B'CD

F(A,B,C,D) = (A + C)(A + D)(B+ D)(A + B + C + D) = (A.A+AC+AD+CD)(B+D)(A+B+C+D) =(A+AC+AD+CD)(B+D)(A+B+C+D) = (AB+ABC+ABD+BCD)(A+B+C+D) = AB+ABD+ ABC+ABCD+AD+ACD+BCD+CD = ABCD+ABCD' +ABC'D+ABC' D' +A' BC'D+AB' C' D' +AB' CD+AB' C'D' +A' BCD+A' B'CD = sigma ( 3,5,7,8,11,12,13,14,15)

Explanation / Answer

//Hope this will helpyou. F = ( 3,5,7,8,11,12,13,14,15) If you have got above expression , it is very easy to generatetruth table. If there is 3 in F, so the output is setto 1 when ABCD have decimal value equal to three. .i.e A B C D         F 0 0   0    0    =>0 0 0   0    1    =>0 0 0   1    0    =>0 0 0   1    1   =>1                    // (0011) 2 = 3, similarly set all 1 tothe 5,7,8,11,12,13,14,15 . .

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