= (1150rev / 1min) (2rad /1rev) (1min/ 60s) = (1150*2*22) /(60*7) = 120.38 rad/s

Question

   = (1150rev / 1min) (2rad /1rev) (1min/ 60s)                 = (1150*2*22) /(60*7)       = 120.38 rad/s    An airplane propeller with blades 2.00m long isrotating at 1150rpm.    Express its angular speed in rad/s.     My question - How did they get the(1150*2*22) / (60*7)    = (1150rev / 1min) (2rad /1rev) (1min/ 60s)                 = (1150*2*22) /(60*7)       = 120.38 rad/s    An airplane propeller with blades 2.00m long isrotating at 1150rpm.    Express its angular speed in rad/s.     My question - How did they get the(1150*2*22) / (60*7)

Explanation / Answer

1150 rpm = 1150 rev / min                = 1150 ( 2 rad ) / ( 60 s ) Since 1 revolution covers 2 radians ofangular displacement and 1 minute = 60 seconds So, 1150 rpm = 1150 ( 2 * 22 / 7 ) rad / 60 s                       = 1`20.42 rad / s

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