6. (12 pts) Components of a Disk The platters spin (say, 5400rpm) The mowed in o

Question

6. (12 pts) Components of a Disk The platters spin (say, 5400rpm) The mowed in or out to positics arm assembly ts Only one hoad sise (which is f Consider a disk with a sector size of 256 bytes, 2000 tracks per surface, 50 sectors per track, five double-sided platters, and average seek time of 10 1. What is the capacity of a track in bytes? 2. What is the capacity of each surface? 3. What is the capacity of the disk? 4. How many cylinders does the disk have? 5. If the disk platters rotate at 5400 rpm (revolutions per minute), what is the maximum rotational delay? 6. If one track of data can be transferred per revolution, what is the transfer rate? ANSWER:

Explanation / Answer

Double Sided Platters = 5

Tracks per Surface=2000

Sectors per Track = 50

Sector Size=256 B

Average Seek Time = 10 ms

1) Capacity of Track = Sectors per Track * Sector Size= 50 * 256 B = 12800B =12.5 KB

2) Capacity of Each Surface = Tracks per Surface * Capacity of Track = 2000 * 12.5 KB = 25000 KB = 24.414 MB

3) Capacity of Disk = Double Sided Platters * 2 * Capacity of Each Surface =5*2*25000=250000KB=244.14 MB

4) Number of Cylinders = Double Sided Platters*2*Tracks per Surface*Sectors per Track

= 5*2*2000*50

=1000000

=106

  

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