20.Below is a screen shot from Wireshark. As can be seen this packet returns the
ID: 3594045 • Letter: 2
Question
20.Below is a screen shot from Wireshark. As can be seen this packet returns the IP address for a domain name in DNS query. Please answer the following question. Assume layers listed are from the TCP/IP Model awing questions. Assume tne says a Vmware 92:94:9f Coo:Oc:29:92:94:9f Frame 3 : 92 bytes on a Ethernet II , Src: Cisco 31:07:33 (00:26:Ob: 31:07:33), DStvia wire (736 bits), 92 bytes captured 736 bits Destination: Vmware_92:94 :9f Co0:0c:29:92:94 :9f) 8 : Cisco,31:07::33 (00:26:Ob:31:07:33) source Type: IP COxO800) Internet Protocol version 4 a Protocol, src Port: domain (53), Dst Port User Datagram 4. Src 4.2.2.1 (4.2.2.1), DSt. - source port: domain (53) Destination port: 62570 (62570) Length: 58 checksum: Oxf3f (validation disabled) a Domain Name System (response) . : .16.0.102 (172.16.0.102) : ) 62570 (62570 (: o.182223000 seconds) Time Transaction ID: Oxf 34d Flags : OxS180 standard query response, Questions: 1 No error Answer RRS: 1 Authority RRS: 0 Additional RRS: 0 a Queries a www.nostarch.com : class type A, IN Name : www.nostarch.com Type: A (Host address) class : COx0001) IN e Answers e www..: class IN, addr 72. 32.92.4 nostarchcom type A, Name: www.nostarch.com Type: A (Host address) class : IN COx0001) Time to live: 1 hour Data length: 4 Addr : 72.32.92. 4 (72.32.92.4) a. what is application layer protocol was used? b. what Internet layer protocol was used? C. what Transport Layer protocol was used?Explanation / Answer
a) Application layer protocol uses is http because host address is a web url.
b) IP4 protocol is used. (See line 6)
c) UDP (User datagram protocol) transport layer protocol was used. (Line 7)
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