Question 1 Write a function count_clear (state) that takes a state of the cargo

Question

Question 1 Write a function count_clear (state) that takes a state of the cargo terminal, and returns an integer count of the number of containers in the given state that are currently clear (i.e., have nothing stacked on top of them) Notes and assumptions Note: The ground is not a container, so it doesn't count. You can assume there are no duplicates. . count-clear ( [ [ ' c1 ' , ' c3 ' ] , [ ' c2' , ' ground' ] , c3 ' , ' ground' ) >>> 2 >> count_clear (['c1', c3'], 'c3', "c2'], ['c2', ground'11) 1 >> count_clear (L'c4', ground'], ['c5', 'ground'], ['c6', 'ground']) 3

Explanation / Answer

It is asking to find all containers which do not have anything stacked on it

For example

In first example

c3 is on top of c1 but there is noting on top of c2 and c3

In seocnd example

c3 is on top of c1 c2 is on top of c3 but there is nothing on c2

so 1

def count_clear(state):
containers = []
d = {}
for bottom, top in state:
containers.append(bottom)
if top != 'ground':
containers.append(top)
d[bottom] = top
  
containers = list(set(containers))
keys = d.keys()
result = len(containers) - len(keys)
return result
print(count_clear([['c1', 'c3'], ['c2', 'ground'], ['c3', 'ground']]))
print(count_clear([['c1', 'c3'], ['c2', 'c2'], ['c2', 'ground']]))
print(count_clear([['c', 'ground'], ['c5', 'ground'], ['c6', 'ground']]))

# code link: https://paste.ee/p/OkX01

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