A. Design a program in C using the “switch” command which will perform any one o

Question

A. Design a program in C using the “switch” command which will perform any one of the following four calculations depending on the value of a “choice” operator:

a) one-time calculation of the equivalent resistance to a user-supplied number and values of resistors connected in series if the user types a value of 1 on the keyboard for the choice operator;

b) calculation in an infinite loop of the equivalent resistance to a user-supplied number and values of resistors connected in series if the user types a value of 2 on the keyboard for the choice operator;

c) one-time calculation of the equivalent resistance to an arbitrary number of resistors connected in series if the user types a value 3 for the choice operator; and calculation in an infinite loop of the equivalent resistance to an arbitrary number of resistors connected in series if the user types a value of 4 on the keyboard for the choice operator.

NOTE The formula for computing the equivalent resistance to n resistors with resistance values R1, R2, …, Rn is Req = R1 + R2 + … + Rn.

B. Draw a flowchart for the program in A above.

Explanation / Answer

Solution of A :

#include<stdio.h>               //to use scanf() and printf()
int main()
{
   int n,choice;
   int j=1;
   int req=0,Req=0;
   int r[100];
   printf("Enter your choice from 1 2 3 4 : ");
   scanf("%d",&choice);
   switch(choice)                       //switch using here
   {
       case 1:
           {
               printf("Enter how many resistors do u want to enter :");
               scanf("%d",&n);
               printf("Enter %d values of Resistors :",n);
               for(int i=1;i<=n;i++)
               {
                   scanf("%d",&r[i]);
                   req=req+r[i];
               }
               printf("Equivalent Resistance will be :%d",req);
               break;
           }
       case 2:
           {
               printf("Enter how many resistors do u want to enter :");
               scanf("%d",&n);
               printf("Enter %d values of Resistors :",n);  
               while(n--)
               {
                   scanf("%d",&r[j]);
                   req=req+r[j];
                   j++;
               }
               printf("Equivalent Resistance will be :%d",req);
               break;
           }
       case 3:                   //arbitrary case (one-time calculation)
           {
               int r1[]={10,20,40,50,70,80};
               int length=sizeof(r1)/sizeof(int);
               Req=Req+r1[0]+r1[1]+r1[2]+r1[3]+r1[4]+r1[5];
               printf("Equivalent Resistance will be :%d",Req);
               break;
           }
       case 4:                       //arbitrary case (infinite loop calculation)
           {
               int k=0;
               int r1[]={17,23,43,56,78,89};
               int length=sizeof(r1)/sizeof(int);
               while(length--)
               {
                   req=req+r1[k];
                   k++;
               }
               printf("Equivalent Resistance will be :%d",req);
               break;
           }
       default:
           printf("Entered Incorrect choice..");
   }
}

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