Show the output of the following programs. 1) abstract class Furniture { abstrac

Question

Show the output of the following programs.

1)

abstract class Furniture { abstract void prnt();}

class Recliner extends Furniture {

void prnt() { System.out.println("I'm a recliner");}

}

class LaZBoy extends Recliner {

void prnt() { System.out.println("I'm a lazboy");}

}

public class furnitureTest2 {

public static void main(String[] args) {

Furniture [] A = { new Recliner(), new Recliner(), new LaZBoy()};

for (int i=0; i<3; ++i)

A[i].prnt();

}

}

2)

class A { int x = 1; }

class B extends A { }

class C extends B { int x = 2;}

public class classTest {

public static void main(String[] args) {

A w = new A(); System.out.println(w.x);

B u = new B(); System.out.println(u.x);

C v = new C(); System.out.println(v.x);

A [] a = { new A(), new B(), new C()};

for (int i=0; i<3; ++i)

System.out.println(a[i].x);

}

}

Explanation / Answer

A. Because the super is abstract, the children even though in an array use their own definition of the function

I'm a recliner

I'm a recliner

I'm a LazBoy

B.

1

1

2

But the loop produces because they inherit from the super class only inside the array.

1

1

1

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