Show the details of your calculations and maintain correct significant figures C

Question

Show the details of your calculations and maintain correct significant figures CHEML 142 (03) 50 Points Q1. The reaction H(g) g2HI(g) has the following rate law: Rate kHI Pts the concentration of H is decreased by a factor 3 while the concentration of I2 is kept same, then (i) what will be the rate law and(ii) how fast or slow will be the new rate? Q2. One student in his experiment found that, when the pressure exerted by helium gas is 5 Pts multiplied by the volume occupied by the helium, the resultant product is 2.32x 135mm Hg.mL.The pressure exerted by helium changes to a new value, which happens to be 750 Torr. What volume will the sample occupy at this pressure, assuming that temperature remains constant? Q3. Explain the following two cases 5 Pts (i) SCUBA divers and Boyle's law (ii) Le Chatellier's Principle

Explanation / Answer

1.

rate law is

Rate = k * [H2]2 * [I2] so you decrease H2 by a factor 3 so the new rate will be

rate = k * [H2 / 3 ] 2 * [I2] or

rate = k * [H2]2 / 9 * [I2]

for the second part,

if you decrease the concentration of a reactant you can be sure that the rate of reaction will decrease, in this case the rate of reaction will decrease by a factor of 9

Q2.

the statement says that the product of the pressure and the volume is 2.32 * 135 = 313.2 mmHg * ml so

this a constant, this means that any time you measure pressure and temperature the product of pressure and volume must be 313.2 so:

PV = constant = 313.2

P is pressure, V is volume

since the new pressure has been provided in torr then we must change it to mm Hg, in this case 1 torr is aproximately 1 mm Hg so 750 torr is 750 mm Hg

so we just need to apply the equation

750 mmHg * Volume = 313.2 mmHg * ml

Volume = 313.2 / 750 = 0.4176 ml

*please post the other questions separately =)

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