Show that the units of specific heat (c) are cal/g-C degree by solving Equation

Question

Show that the units of specific heat (c) are cal/g-C degree by solving Equation 2 for c and substituting the appropriate units for Q, m and Delta T. A. 2.00-kg lead block and a 2.00-kg copper block have the same temperature of 22 degree C. You wish to heat both blocks to 92 degree C. Which of the following statements is correct (circle its identifying letter)? (a) The lead block will require more heat than the copper block. (b) The lead block will require less heat than the copper block. (c) The two blocks will require the same amount of heat. Explain your answer.

Explanation / Answer

Ans (a) Q in calories, m is in grams and delta T in degree celcius

Q=m*c*delta T

c=Q/(m*delta T)=calorie/(gram* degee celcius)

(b) specific heat of lead= 129 J/Kg C

heat of lead block=m*c* deltaT=2*129*(92-22)=18060 J=18.060 KJ

specific heat of copper=385 J/Kg C

heat of copper block=m*c*deltaT=2*385*(92-22)=53900 J=53.900 KJ

option (b) is correct

  

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