...in which a IntList class is defined that contains an overloaded [] operator.

Question

...in which a IntList class is defined that contains an overloaded [] operator. What is the output of this program?

#include <iostream>
using namespace std;

class IntList
{
private:
int list[1];
public:
IntList() {list[0] = 0;}
int& operator[] (const int index) {return list[index];}
};

int main()
{
IntList list;
cout << list[0] << endl;
list[0] = 1;
cout << list[0] << endl;
return 0;
}

I ALREADY figured out the output, which is:

0

1

I need help with this:

Notice that the overloaded [] operator returns a reference. Change the [] operator to return a value instead and explain what happens in that case. Explain why the ability to return by reference is essential to be able to implement such an operator. Can anything similar be done in Java?

Explanation / Answer

your ouput is correct

when is value is returned , calling list[0]=1 will produce error lvalue required because now list[0] is some integer value not a variable or a referance which can't be assigned , This is because return by reference is essential in such type of operartion.

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